SOLUTION: Given: ∆AKM, R = 2, m∠A = 33°, O∈AM. Find: perimeter of ∆AKM https://lh3.googleusercontent.com/XxKrlU8bFG1SlkyIN7TnUgujgwFyLSlOVvHPOX7Z5ROrqCGAlXuvwvfMN

Question 1150085: Given: ∆AKM, R = 2,
m∠A = 33°, O∈AM.
Find: perimeter of ∆AKM
https://lh3.googleusercontent.com/XxKrlU8bFG1SlkyIN7TnUgujgwFyLSlOVvHPOX7Z5ROrqCGAlXuvwvfMN9C3S4fiiK7Zbg=s97
Answer by Edwin McCravy(20066) (Show Source): You can put this solution on YOUR website!

 

∆AKM is a right triangle for it is inscribed in semicircle O.

AM = diameter of semi-circle O = 2R = 2(2) = 4









The perimeter of a triangle is the sum of the three sides.





Approximately 9.533238412

Edwin

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