SOLUTION: Find the domain and solve: (x+3)^(√2x+5) =(x+3)^x+1

Algebra.Com
Question 1146398: Find the domain and solve:
(x+3)^(√2x+5) =(x+3)^x+1

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Can't help you. Your equation is ambiguous.

I have to assume that the "x + 1" term in the RHS is supposed to be contained in parentheses, but even given that your equation could be:



or



or



Repost and use parentheses to avoid ambiguity.


John

My calculator said it, I believe it, that settles it


RELATED QUESTIONS

f(x)=x^2+3/2x-1 Find the... (answered by Fombitz)
f(x)=(x+3)(x-5)/(x+1)(X-4) find the domain and... (answered by lwsshak3)
find the domain of... (answered by edjones)
find the domain of... (answered by jim_thompson5910)
Find the domain of these functions. f(x)=7-x^2 g(x)=2x+1/x-1 f(x)=sqrt(x-5)... (answered by solver91311)
f(x)=1/2x^3-5 Find inverse, domain, and the range for f and f^-1 Thank you... (answered by stanbon)
Find the domain and range of A): 1/(√(3-2x-x^2)) B):... (answered by MathLover1)
Find the Domain of the function. f(x)= 3-1/2x if x is less than and greater than 2... (answered by stanbon)
find the domain and range of f(x)=2x+3 (answered by crabbyoldgamer)