The intersection point is easy to find : for it, add and subtract the given equations. You will get the intersection point (4,1).


To find its distance from the line 3x + 2y = 5, use this formula


    d = ,     (1)


which is valid for any point (p,q) in a coordinate plane and any line Ax + By + C = 0.


In your case, p= 4, q= 1, A = 3, B= 2, C= -5,  so the distance is


    d =  =  units.