SOLUTION: find the smallest positive x(in terms of π)for which sinx=-sqrt( 3 )/2
a.x=2π/3,b.x=4π/3,c.x=5π/6,d.x=7π/6
I believe the correct answer is A.
Question 1144204: find the smallest positive x(in terms of π)for which sinx=-sqrt( 3 )/2
a.x=2π/3,b.x=4π/3,c.x=5π/6,d.x=7π/6
I believe the correct answer is A. Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52805) (Show Source): You can put this solution on YOUR website! .
find the smallest positive x(in terms of π)for which sin(x) = -sqrt( 3 )/2
a.x=2π/3,b.x=4π/3,c.x=5π/6,d.x=7π/6
~~~~~~~~~~~~~~~
The correct answer is b. x = .
What you do believe, it does not matter, since you don't know the subject.
A 60 degree reference angle in any quadrant will give you a sine value of or .
Sine is positive in quadrants I and II; so the smallest positive angle with a sine of will be in quadrant III.
A 60 degree reference angle in quadrant III is 240 degrees.
Since the answer choices are in radians, 240 degrees is 4π/3 radians.
So answer b.
Note for your answer a the reference angle is the correct 60 degrees or π/3 radians; but it is in quadrant II, where the sine value is positive, not negative.