SOLUTION: 1+cosx /sinx + sinx / 1+cosx =
2sinx
2cscx
2secx
2cosx
Algebra.Com
Question 1142952: 1+cosx /sinx + sinx / 1+cosx =
2sinx
2cscx
2secx
2cosx
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In the future, please use parentheses so that we don't have to guess what terms belong in the numerators and denominators of your fractions.
}{\sin(x)}\ +\ \frac{\sin(x)}{1\,+\,cos(x)})
\)^2\ +\ \sin^2(x)}{\sin(x)\(1\,+\,cos(x)\)})
\,+\,\cos^2(x)\ +\ \sin^2(x)}{\sin(x)\(1\,+\,cos(x)\)})
}{\sin(x)\(1\,+\,cos(x)\)}\ \ \ \ )
Note: Pythagorean Identity
\)}{\sin(x)\(1\,+\,cos(x)\)})
}\ =\ 2\csc(x))
John
My calculator said it, I believe it, that settles it
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