SOLUTION: Find all solutions of the equation in the interval [0,2π). -cosx = -sin^2x-1 Write your answer in radians in terms of π. If there is more than one solution, separate with c

Question 1142370: Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Write your answer in radians in terms of π.
If there is more than one solution, separate with commas.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Add parentheses:
-cos(x) = -sin^2(x) - 1
Is that what you meant?
------------
cos(x) = sin^2(x) + 1

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Can you do the rest?
======================
Do NOT say this:
If there is more than one solution, separate with commas.
What would we do if we don't have any commas?

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