SOLUTION: a parking lot has a perimeter of 16000ft. the width is 40ft more than twice the length. find the dimensions. please show your work here's what I have done p=2l+2w=16000 l+w

Question 1140088: a parking lot has a perimeter of 16000ft. the width is 40ft more than twice the length. find the dimensions.
please show your work
here's what I have done
p=2l+2w=16000
l+w=8000
l=2w+8000
2w+40+w=8000
3w=7960
7960/3=2653.3
l=2(2653)+8000
l=13306

Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!

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, width is 40ft more than twice the length.
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.
.

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return again to w=2L+40 and evaluate width.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

a parking lot has a perimeter of .
=> where is length and width

if the width is more than the length, we have

then

check:

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