SOLUTION: for the one to one function f(X)=x+1/2x-3 a)find the inverse f^-1 f(x)=x+1/2x-3 y=x+1/2x-3 x=y+1/2y-3 divide 2y-3 on both sides =(2y-3)x=y+1 -1 from both sides =2xy-1-3x=y-2

Question 1139660: for the one to one function f(X)=x+1/2x-3
a)find the inverse f^-1
f(x)=x+1/2x-3
y=x+1/2x-3
x=y+1/2y-3
divide 2y-3 on both sides
=(2y-3)x=y+1
-1 from both sides =2xy-1-3x=y-2xy
factor out y-2xy=-1-3x=y(1-2x)
divide 1-2x on both sides =y=-3x-1/-2x+1
-1/-1(y=3x+1/2x-1
f^-1=3x+1/2x-1
Now graph f and graph f^-1
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
a)find the inverse
.....replace with
.......swap and
....solve for

=>
graph:
yu need two points on a line; so, choose and find
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plot points and draw a line through

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