SOLUTION: Solve for 0≤x<2pi: cosx·sinx = sin^2(x)

Question 1138385: Solve for 0≤x<2pi: cosx·sinx = sin^2(x)
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!

One of those 2 factor must be zero for the product to be zero.
if and only if
When ,
if and only if or , and
if and only if or
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