SOLUTION: Find the vertex, focus, directrix, and focal width of the parabola. choices below (5 points) negative 1 divided by 16 times x squared = y Vertex: (0, 0); Focus: (0, -4); Directr

Question 1138077: Find the vertex, focus, directrix, and focal width of the parabola. choices below (5 points)
negative 1 divided by 16 times x squared = y
Vertex: (0, 0); Focus: (0, -4); Directrix: y = 4; Focal width: 16

Vertex: (0, 0); Focus: (-8, 0); Directrix: x = 4; Focal width: 64

Vertex: (0, 0); Focus: (0, 4); Directrix: y = -4; Focal width: 4

Vertex: (0, 0); Focus: (0, -4); Directrix: y = 4; Focal width: 64

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Find the vertex, focus, directrix, and focal width of the parabola. choices below

The standard form is , where the focus is (,) and the directrix is .
given:

=>,=>the vertex at:(, )
=>
a focus at (, )=(, )
a directrix at =>

The focal width of a parabola is the length of a segment that is parallel to the directrix and passing through the focus of a parabola. The length of this segment is units, or four time the length from the focus to the vertex.
focal width:

answer:Vertex: (0, 0); Focus: (0, -4); Directrix: y = 4; Focal width: 16

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