SOLUTION: Solve cos2x=-cosx for the interval 0 ≤ x < 2pi.
Algebra.Com
Question 1138005: Solve cos2x=-cosx for the interval 0 ≤ x < 2pi.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
for the interval
..........use the following identity :
.......let
solutions:
if =>
if=>
since , we have
or
if , and , then
if , and, than ,
combine all solutions: , ,
RELATED QUESTIONS
Solve cos2x = -cosx for the interval 0 ≤ x <... (answered by MathLover1)
Solve cos2x = -cosx over the interval 0 ≤ x <... (answered by MathLover1)
Solve cos2x=-cosx over the interval 0 ≤ x <... (answered by MathLover1)
cos2x = -cosx for 0 ≤ x < 2pi: (Round to nearest... (answered by Alan3354)
Solve for x in [0, 2pi]:... (answered by jsmallt9)
Solve sin3x+sinx=cosx for... (answered by Edwin McCravy)
how do you find all the solutions for the interval sinx cosx - cosx = 0, with the... (answered by rothauserc)
Please explain how to solve the equation for exact solutions over the interval [0, 2pi).
(answered by Fombitz)
Solve algebraically :
3 cos2x+cosx+1=0
(answered by srinivas.g)