SOLUTION: solve 4 cos2 θ + 2 sin θ = 3 for 0° ≤ θ ≤ 360°

SOLUTION: solve 4 cos2 θ + 2 sin θ = 3 for 0° ≤ θ ≤ 360°

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Question 1137965: solve 4 cos2 θ + 2 sin θ = 3 for 0° ≤ θ ≤ 360°
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

solve for ° ≤ ≤ °

Use the following identity :

.........let

.....solve with the quadratic formula

solutions:
=>
=>
so,
or

: if ° , then

=>° ,
and
° => °
: if ° , then ° or °

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