SOLUTION: Solve the equation x^4-13x^2+30? List all real solutions, separated by commas? x=

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Question 1136757: Solve the equation x^4-13x^2+30?
List all real solutions, separated by commas?
x=

Found 3 solutions by Boreal, Alan3354, ikleyn:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!

this factors into an x^2- and an x^2- because the middle term is negative and last term is positive. One can use a u substitution where u=x^2
(u-10)(u+3)=0 The given is an expression, the equal sign 0 makes it an equation.
u=10 and -3
x^2=10
x+=/- sqrt (10) or (-sqrt(10), + sqrt (10)) ANSWER.
The other two solutions are complex/imaginary

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
That is not an equation.
Equations have equal signs.
---
x^4-13x^2+30 = 1 is an equation.
x^4-13x^2+30 = 5 is an equation.
x^4-13x^2+30 = 100 is an equation.

Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

            First,  it is not an equation,  since it has no right side and the equality sign.

            So,  we can talk about a polynomial,  but not about equation.

            And the question,  if to formulate it correctly,  should be  THIS :

                Find the roots of this polynomial.

            Second, the solution and the answer by @Boreal both are incorrect, since his factoring is incorrect.

            Below find the correct solution.


Introduce new variable  u = x^2.

Then your polynomial takes the form


    u^2 - 13u + 30


It can be factored in this way


    u^2 - 13u + 30 = (u-3)*(u-10) 


so, it has the roots  u = 3  and  u = 10, both positive.


It means, that the original polynomial has 4 (four) real roots  , ,    and  .    ANSWER

Solved.


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