SOLUTION: Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11). A.y squared over forty minus x squared over eighty one = 1 B.y square

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Question 1136096: Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11).

A.y squared over forty minus x squared over eighty DISABLED_event_one= 1

B.y squared over eighty one minus x squared over one hundred and twenty DISABLED_event_one= 1

C.y squared over eighty one minus x squared over forty = 1

D.y squared over one hundred and twenty one minus x squared over eighty DISABLED_event_one= 1

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Find an equation in standard form for the hyperbola with
vertices at (, ±) and
foci at (, ±).
The standard form of the equation for this type of hyperbola given the center is at the origin is:


Your coordinates of the vertices are (, ±) and (, ±) making and





so your equation is:


answer: C.y squared over eighty one minus x squared over forty = 1


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