SOLUTION: Write the sum using summation notation, assuming the suggested pattern continues.
9 - 18 + 36 - 72 + ... (2 points)
choices are below
summation of nine times two to the powe
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Question 1135462: Write the sum using summation notation, assuming the suggested pattern continues.
9 - 18 + 36 - 72 + ... (2 points)
choices are below
summation of nine times two to the power of n from n equals zero to infinity
summation of nine times negative two to the power of the quantity n plus one from n equals zero to infinity
summation of nine times two to the power of the quantity n plus one from n equals zero to infinity
summation of nine times negative two to the power of n from n equals zero to infinity
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
^n)
Which is the sum of 9(-2)^n from n = 0 to infinity (aka the terms go on forever)
Therefore the answer is choice D
Note how plugging n = 0 into 9(-2)^n leads to
9(-2)^n = 9(-2)^0
9(-2)^n = 9(1)
9(-2)^n = 9
So the first term to be added is 9
Then trying n = 1 leads to
9(-2)^n = 9(-2)^1
9(-2)^n = 9(-2)
9(-2)^n = -18
Making -18 to be the second term to be added. So far we have the expression
Trying n = 2 leads to
9(-2)^n = 9(-2)^2
9(-2)^n = 9(4)
9(-2)^n = 36
We add on 36 as the third term. So far we have the expression
Trying n = 3 leads to
9(-2)^n = 9(-2)^3
9(-2)^n = 9(-8)
9(-2)^n = -72
We add on -72 as the fourth term. So far we have the expression
As n heads off to infinity, we end up with the expression
side notes
- The sequence {9, -18, 36, -72, ...} is geometric.
- The starting term is a1 = 9
- The common ratio is r = -2
- The common ratio can be found by dividing any term by its previous one (eg: term3/term2 = 36/(-18) = -2)
- The infinite series 9-18+36-72+... diverges meaning the sum of the infinitely many terms does not approach a fixed value (ie the sum keeps drastically changing as you add on more terms). The infinite series only converges if -1 < r < 1, but r = -2 is outside this range.
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