SOLUTION: Write the complex number in the form a + bi.
4[cos (-135°) + i sin (-135°)] Which answer is it, these are the choices for the problem below.
A.negative two square root tw
Algebra.Com
Question 1134132: Write the complex number in the form a + bi.
4[cos (-135°) + i sin (-135°)] Which answer is it, these are the choices for the problem below.
A.negative two square root two plus two square root two i
B.negative two square root two minus two square root two i
C.negative square root two minus square root two i
D.negative square root two plus square root two i
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
cos (-135) is -sqrt(2)/2 and sin (-135) is - sqrt(2)/2
-2 sqrt(2)-2i sqrt(2)
this is -2 sqrt(2)-2 sqrt(2)*i B
it can also be written as -2sqrt(2)[1+i]
RELATED QUESTIONS
Write the complex number in the form a + bi.
4[cos (-135°) + i sin... (answered by Boreal)
Write the complex number in the form a + bi.
five divided by two(cos 150° + i sin... (answered by josmiceli)
Write the complex number in the form a + bi.
square root of six (cos 315° + i sin... (answered by MathLover1)
Let z = 4(cos 135° + i sin 135°) and w = 3(cos 45° + i sin 45°). Write the rectangular... (answered by Alan3354)
Let z = 4(cos 135° + i sin 135°) and w = 3(cos 45° + i sin 45°). Write the rectangular... (answered by Alan3354)
Write in rectangular form:... (answered by Edwin McCravy)
1. Find the modulus and argument of the following complex numbers, and write them in... (answered by ikleyn)
The conjugate of 5 + 6i is
Find the product (2 + i)(3 + 4i). Give your answer in... (answered by stanbon)
Write the complex number in the form a + bi.
4[cos (-135°) + i sin (-135°)] this are... (answered by Boreal)