SOLUTION: find x for {{{tan((x/2)-(pi/2))=sqrt(2)}}}
I got {{{x=2arccot(-sqrt(2)) + 2*pi*n}}}where n is all integers, but it's wrong?
i changed tan to -cot so it would be cot(x/2)= -sq
Algebra.Com
Question 1132674: find x for
I got where n is all integers, but it's wrong?
i changed tan to -cot so it would be cot(x/2)= -sqrt2 and then solved x for that.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
x = 2(pi*n -cot^(-1) (sqrt(2)), where n is an element of Z
:
Here how to get this answer
:
-cot(x/2) = sqrt(2)
:
Multiply both sides by -1 to simplify the equation.
:
cot(x/2) = -sqrt(2)
:
Eliminate the cotangent from the left hand side
;
Take the inverse cotangent of both sides
:
x/2 = pi * n -cot^(-1)(sqrt(2)) for n an element of Z
:
Solve for x
:
x = 2 * pi * n -2 * cot^(-1)(sqrt(2)) for n an element of Z
:
x = 2 * (pi * n -cot^(-1)(sqrt(2)) for n an element of Z
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