SOLUTION: (cos2x+sin2x)^2=1+sin4x

Algebra.Com
Question 1130401: (cos2x+sin2x)^2=1+sin4x
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!



Double Angle Identities
,->
->








Answer by ikleyn(52824)   (Show Source): You can put this solution on YOUR website!
.
 =  =  +  = 1 + 4*sin(2x).

Completed, proved and solved.


RELATED QUESTIONS

(sin2x+sin4x)/(cos2x+cos4x)=tan3x (answered by Alan3354)
Prove the following identity: {{{(1-sin2x)/(cos2x) =... (answered by Alan3354)
cos2x-cos4x/sin2x+sin4x= a. cot x b. tan x c. sin x d. cos... (answered by Solver92311)
cos2x+cos4x -------------- = sin2x-sin4x a. cot x b.-cot x c. sin x d.- tan x (answered by MathLover1,ikleyn)
cos2x-cos4x -------------- = sin2x+sin4x a. cot x b. tan x c. sin x d. cos... (answered by math_helper)
Factor the trigonometric expression and simplify. 1 - 2 sin2x +... (answered by stanbon)
verify:... (answered by Alan3354)
Sole for x:... (answered by tommyt3rd)
sinx+sin2x=1,then cos2x+xos4x=? (answered by Alan3354)