SOLUTION: The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x − 0.5x^2. Recall that profit is revenue minus cost. Set up a quadratic equation

Question 1129290: The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x − 0.5x^2. Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $800.
x =
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x − 0.5x^2. Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $800.
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Profit:: P(x) = 100x-0.5x^2 - (40x+800)
P(x) = -5x^2 +60x - 800
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Solve for "x"::
-5x^2+60x - 800 = 800
-5x^2 + 60x - 1600 = 0
Note:: This quadratic has no Real Number solutions.
Please check your post.
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Cheers,
Stan H.
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Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

if and the revenue
profit is

profit of

...factor

write as , than we have

solutions:
=>
=>

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SOLUTION: The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x &#8722; 0.5x^2. Recall that profit is revenue minus cost. Set up a quadratic equation

SOLUTION: The cost function for a certain company is C = 40x + 800 and the revenue is given by R = 100x − 0.5x^2. Recall that profit is revenue minus cost. Set up a quadratic equation