SOLUTION: what are the solutions of sin(4x) + sin(x) = 0 between 0 and pi
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Question 1127697: what are the solutions of sin(4x) + sin(x) = 0 between 0 and pi
Found 2 solutions by addingup, ikleyn:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
sin(4x) + sin(x) = 0
Rewrite the equation:
4x = (sin^−1)(sin(x)). The right hand side is either x or π−x, or either of these plus any integer multiple of 2π. So, in the following equation find all values of n that give results between 0 and π:
4x = x + 2nπ
or
4x=π−x + 2nπ
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
example:
x = (2nπ)/3 or x = ((2n+1)π)/5
Answer by ikleyn(52858) (Show Source): You can put this solution on YOUR website!
.
What I see in the post by @addingup, is not a correct solution.
It is even not a Math - it is far away from any Math standard.
You can (actually, you MUST) ignore it - it does not deserve any discussion.
For a correct solution see my post under the link
https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1127695.html
https://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.1127695.html
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