SOLUTION: Evaluate the integral 1/sqr(x^2+8x+17) dx from bounds x=-1 to x=1

Question 1121446: Evaluate the integral 1/sqr(x^2+8x+17) dx from bounds x=-1 to x=1

Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.
There is a FANTASTIC site

https://www.integral-calculator.com/

which will do EVERYTHING calculating and evaluating integrals for you with explanations and steps FREE of CHARGE.

Still, if you do not read (and work on) standard University Calculus textbook (like those written/authorized by Stewart),
you, most likely, will not know the subject.

RELATED QUESTIONS
Evaluate the integral 1/sqr(x^2-3x+2) dx from bounds x=2.5 to... (answered by ikleyn)

Evaluate the Integral from [1, ln2] 2e^x... (answered by Alan3354)

From a Putnam competition: Evaluate the integral {{{int(ln(x+1)/(x^2+1), dx,... (answered by robertb)

Evalute integral sin^2 (x) * cos^2 (x) dx from bounds 0 to pi/3 by using : cos^2 (x) =... (answered by math_tutor2020)

Find integral... (answered by solver91311)

Find integral... (answered by Alex.33,solver91311,Edwin McCravy)

Evaluate : int(x^(x-2) * (x+1+(x+ln(x²/e))²)) dx : int means integral (answered by solver91311)

how to get this definite integral, i need the steps not just the answer... (answered by Fombitz)

determine whether the integral from 1 to 9 for the function 1/cuberoot(x-9)dx is... (answered by Edwin McCravy)