SOLUTION: Solve the equation in the interval (0 degrees, 360 degrees) sin^2 theta-sin theta-12=0

Question 1120084: Solve the equation in the interval (0 degrees, 360 degrees)
sin^2 theta-sin theta-12=0
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52858) (Show Source): You can put this solution on YOUR website!
.
Solve the equation in the interval (0 degrees, 360 degrees)
sin^2 theta-sin theta-12=0
~~~~~~~~~~~~~~~

This equation has no real solutions.

See the plot below

Plot y = (red) and y = 12 (green) on the interval [0,).

Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!

Did you type the equation correctly?

The maximum value of sin^2 theta is 1; the maximum value of |sin theta| is 1.

The maximum value of sin^2 theta - sin theta is 1+1 = 2.

Obviously the equation has no solutions.
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