SOLUTION: Solve the following equations for 0c≤ x ≤ 180
a) 3sinθ = 2cosθ
b) sinθ - 4cosθ = 0
Algebra.Com
Question 1118671: Solve the following equations for 0c≤ x ≤ 180
a) 3sinθ = 2cosθ
b) sinθ - 4cosθ = 0
Found 2 solutions by t0hierry, greenestamps:
Answer by t0hierry(194) (Show Source): You can put this solution on YOUR website!
3 sin(theta) = 2 cos(theta)
9sin^2 theta = 4 cos^2 theta
9sin^2 theta = 4(1 - sin^2 theta)
13 sin^2 theta = 4
sin theta = 2/sqrt(13)
sin theta = 4 cos theta
sin^2 theta = 16 cos^2 theta
sin^2 theta = 16 - 16 sin^2 theta
17 sin^2 theta = 16
sin theta = 4/sqrt(17)
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
x = arctan(2/3) = 0.588 radians, to 3 decimal places
x = arctan(4) = 1.3258 radians, to 4 decimal places
RELATED QUESTIONS
Solve the following equations for 0 ≤ θ ≤ 180 degrees.
6.a. sin^2... (answered by Theo)
Please help me
Solve the following equation for x, if 0 ≤ x ≤ 2π... (answered by lwsshak3,josgarithmetic)
Solve the following equations given that 0° ≤ θ < 360° :
A) cos^2 θ - 1 (answered by lwsshak3)
Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0
Note:... (answered by MathLover1)
Solve the following equation exactly for 0≤θ≤2Π with θ in... (answered by lwsshak3)
Solve the equation for 0 ≤ θ ≤ 2π.
cosθ - sinθ = 0 (answered by Fombitz)
Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 =... (answered by MathLover1)
Solve the following equations given that 0° ≤ θ < 360° :
A) cos θ =... (answered by ikleyn)
What values for theta( 0 ≤ theta ≤ 2pi) satisfy the equations?
1.4cos... (answered by ikleyn)