SOLUTION: If z1 = 4cis300° and z2 = 2cis30° , find z1z2 in its POLAR FORM: rcis(theta).

Algebra ->  Trigonometry-basics -> SOLUTION: If z1 = 4cis300° and z2 = 2cis30° , find z1z2 in its POLAR FORM: rcis(theta).      Log On


   

Question 1117279: If z1 = 4cis300° and z2 = 2cis30° , find z1z2 in its POLAR FORM: rcis(theta).
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
If z1 = 4cis300° and z2 = 2cis30° , find z1z2 in its POLAR FORM: rcis(theta).
~~~~~~~~~~~~~~~~~~~~ 

z1*z2 = 4*2*cis(300°+30°) = 8*cis(330°).


Multiply modules and add arguments.