SOLUTION: How does one prove that {{{(tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cosA}}}?

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Question 1114647: How does one prove that ?
Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
How does one prove that (tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cosA
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Cross-multiply to get::
cos(A)(tan(A)+sec(A)-1) = (1+sin(A))(tan(A)-sec(A)+1)
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sin(A) +1 -cos(A) = tanA -secA +1 + sin^2A/cos(A) - tan(A) + sin(A)
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-cos(A) = -sec(A) + sin^2(A)/cos(A)
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-cos^2(A) = -1 + sin^2(A)
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sin^2(A)+cos^2(A) - 1 = 0
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0 = 0
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Cheers,
Stan H.
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Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Start with the left side.



Try multiplying by .



Just a start. I have not gone any further with this. Maybe you can and will finish.

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