SOLUTION: Solve 3sin^2x + 2cosx + 1 = 0. For x is less than or equal to 360

SOLUTION: Solve 3sin^2x + 2cosx + 1 = 0. For x is less than or equal to 360

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Question 1112880: Solve 3sin^2x + 2cosx + 1 = 0. For x is less than or equal to 360
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve 3sin^2x + 2cosx + 1 = 0. For x <= 360
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Sub 1 - cos^2(x) for sin^2(x)
--> a quadratic in cos(x)
Solve for cosine, sub u for cos(x) if that is helpful.
Solve for x.
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