SOLUTION: In triangle ABC, a=8, b=9, and cosC= 2/3. Find c.

Algebra.Com
Question 1105984: In triangle ABC, a=8, b=9, and cosC= 2/3. Find c.
Answer by ikleyn(52842)   (Show Source): You can put this solution on YOUR website!
.
Cosine law:

c^2 = a^2 + b^2 - 2ab*cos(C) = 8^2 + 9^2 - .


Complete these calculations on your own.

--------------
On cosine law,  see the lessons
    - Proof of the Law of Cosines revisited
    - Solve triangles using Law of Cosines
in this site.


RELATED QUESTIONS

in triangle ABC, a=2, b=3, and c=4. What is the value of... (answered by stanbon)
in triangle ABC, a = 7, b = 5, and c = 8. What is the value of... (answered by Alan3354)
In a triangle if CosA/a = CosB/b = CosC/c and if a = 2 then find the area of triangle... (answered by robertb)
In ΔABC, Given (a/cosA)=(b/cosB)=(c/cosC) . Prove that ΔABC is an equilateral... (answered by Edwin McCravy)
For any triangle ABC, we have cosA + cosB + cosC =1+4SinA/2SinB/2SinC/2 and SinA/2 +... (answered by robertb)
Would you please help me with this question.. In triangle ABC, AC = 18, BC =10,... (answered by stanbon)
In the right triangle ABC, m (answered by Fombitz)
In triangle ABC, a = 6.8 , b = 15 , and sin C = 1/3. Find the area of triangle... (answered by Alan3354)
If angles A, B, and C are the sides of a triangle such that sin(A+B)=1/cosC and... (answered by venugopalramana)