SOLUTION: Prove the identity
(sin A - cos A)/(sin A) + (cos A - sin A)/(cos A) = 2 - sec A csc A
Algebra.Com
Question 1104648: Prove the identity
(sin A - cos A)/(sin A) + (cos A - sin A)/(cos A) = 2 - sec A csc A
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Prove the identity
(sin A - cos A)/(sin A) + (cos A - sin A)/(cos A) = 2 - sec A csc A
(1 - cot) + (1 - tan) = 2 - 1/(sin*cos)
2 - tan - cot = 2 - 1/(sin*cos)
tan + cot = 1/(sin*cos)
Multiply thru by sin*cos
sin^2 + cos^2 = 1
I'm convinced.
RELATED QUESTIONS
sin^2x - sin^4x = (cos^2)(sin^2x)
sin^2x - (sin^2x)(sin^2x) = (cos^2x)(sin^2x)
sin^2x (answered by jim_thompson5910)
Prove the identity:
sin(A)·tan(A) + cos(A) =... (answered by Edwin McCravy)
Prove or disprove without a calculator.
(sin theta/csc 2theta)-(cos 2theta/sec theta)=... (answered by solver91311)
prove the following as an identity;
cos(a-b) - cos(a+b) =... (answered by Cromlix)
Prove that sin^A cos^ B – cos^A sin^B = sin^A - sin^ B
(answered by ikleyn)
Verify this trigonometric identity... (answered by robertb)
establish each identity
A) 1 - sin theta over cos theta + cos theta over 1 - sin... (answered by lwsshak3)
Sec A + tan A =2 find sin A + cos A ?
(answered by KMST)
csc A cos A / sec A sin A = (csc^2A-1)
(answered by Alan3354)