SOLUTION: (sin(x))^2=1/25 [0,2pi] x=

Question 1103953: (sin(x))^2=1/25 [0,2pi]
x=
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(sin(x))^2=1/25 [0,2pi]
---------
Usually written sin^2(x) = 1/25
sin(x) = 1/5
sin(x) = -1/5
---------
Use a calculator.
RELATED QUESTIONS
0 2pi: sin^2(x)-sq root of 3... (answered by lwsshak3)

Solve: sin(x) + 2^(1/2) = -sin(x); domain (0,... (answered by stanbon)

Find all exact solutions on (0, 2pi) sec(x) sin(x) - 2 sin(x) =... (answered by Boreal,MathLover1)

1.Solve the equation 2cos x-1=0, 0 (answered by stanbon)
Solve all equations for (0, 2pi) sin(x + (pi/4)) + sin(x - (pi/4)) = 1 (answered by lwsshak3)
Solve the following for 0 < x < 2pi (sin x + cos x)^2 =... (answered by lwsshak3,Alan3354)
find all solution in radians if {{{0 (answered by tommyt3rd)
Solve on the interval [0, 2pi] Sin*2x - sin x + 1=... (answered by lwsshak3)
sin(x/2) + cos(x) = 0 Give all answers From 0 to 2pi (answered by lwsshak3)
Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =<... (answered by lwsshak3)