SOLUTION: Solve the following equation for the interval [0, 2pi] :
2cotx + sec^2x = 0
How can I solve this algebraically? Help would be really appreciated!
Algebra.Com
Question 1103338: Solve the following equation for the interval [0, 2pi] :
2cotx + sec^2x = 0
How can I solve this algebraically? Help would be really appreciated!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
2cotx + sec^2x = 0
2cotx + tan^2x + 1 = 0
2 + tan^3 + tan = 0
tan^3 + tan = -2
tan(x) = -1 (by inspection)
x = 3pi/4, 7pi/4
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