.
If cos(t)=-5/6 where pi < t < 3pi/2 , find the values of the following trigonometric functions.
cos(2t) =
sin(2t)=
cos(t/2)=
sin(t/2)=
~~~~~~~~~~~~~~~~
You are given that cos(t) = and the angle "t" is in QIII.
Then sin(t) = = = = = .
Notice that I put the sign "-" (minus) at sqrt, since the function sine is NEGATIVE in QIII.
The next steps are straightforward.
a) cos(2t) = cos^2(t) - sin^2(t) = = = = .
b) sin(2t) = 2*sin(t)*cos(t) = = .
c) cos(t/2) = = = = = = = .
Again, the sign is "-" at sqrt, since cosine is NEGATIVE function in QII, where the angle t/2 is.
d) sin(t/2) = = = = = = = .
The sign is "+" at sqrt, since the sine function is POSITIVE in QII, where the angle t/2 is.
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There are two useful groups of lessons in this site, relevant to this problem.
First group is the lesson
- FORMULAS FOR TRIGONOMETRIC FUNCTIONS
and all associated lessons (links) with it.
The second group is these lessons
- Calculating trigonometric functions of angles
- Advanced problems on calculating trigonometric functions of angles
- Evaluating trigonometric expressions
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the parts of this online textbook under the topics
"Trigonometry. Formulas for trigonometric functions" and "Trigonometry: Solved problems".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.