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Instruction from Alan is correct, but I think that for the person who posted it, it is not enough.
So I put the entire solution here.
Introduce new variable u = cos(x). Then your equation takes the form
6u^2 + 7u + 2 = 0.
It is QUADRATIC EQUATION for the unknown "u". To solve it, apply the quadratic formula
= = .
You have two solutions for u:
1) = = = .
It leads us to equation cos(x) = which has TWO solutions x = 120 degs and/or x = 240 degs in the given interval.
2) = = = .
It leads to equation cos(x) = which has TWO solutions x = arccos(-2/3) degs and/or x = arccos(-2/3) degs + 180 degs in the given interval.
Answer. The given equation has 4 (four) solutions:
x= 120 degs; x= 240 degs; x= arccos(-2/3) degs and x = arccos(-2/3) degs + 180 degs.
Solved.