SOLUTION: prove the identity [cot(X) + cot(Y)] / [tan(X) + tan(Y)] = cot(X)cot(Y)

Question 1099507: prove the identity
[cot(X) + cot(Y)] / [tan(X) + tan(Y)] = cot(X)cot(Y)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
prove the identity
[cot(X) + cot(Y)] / [tan(X) + tan(Y)] = cot(X)cot(Y)
===============
Multiply by [tan(X) + tan(Y)]
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cot(x) + cot(y) = cot(y) + cot(x)
I'm convinced.

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