SOLUTION: If cosx=-3/5, and x is in between 180 and 360 degrees, find the value of sinx

Question 1099379: If cosx=-3/5, and x is in between 180 and 360 degrees, find the value of sinx
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
cos x is negative in the third quadrant, not the fourth, and sin x is negative in the third quadrant.
cos^2x + sin ^2 x=1
Therefore, sin ^2 x=1=9/25=16/25
sin x=-4/5
Answer by ikleyn(52834) (Show Source): You can put this solution on YOUR website!
.

. . . then the angle x terminates in QIII, where sine is negative function, and sin(x) = = = = -= = .

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