SOLUTION: 1+cos ^2Q = 2(cos ^4Q+sin ^4Q)
Algebra.Com
Question 1091965: 1+cos ^2Q = 2(cos ^4Q+sin ^4Q)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Thx for letting us know.
RELATED QUESTIONS
3/4q+1/2q^2=1/8q (answered by stanbon)
simplify by removing factors of 1... (answered by RAY100)
Simplify by removing factors of 1.
2q^2+2q/14q^2+4q.
the simplified form is:... (answered by Tatiana_Stebko)
Simplify... (answered by jim_thompson5910)
P^4q^-7/(3p)^-2q (answered by Boreal)
Please help me solve this equation Thank you
Factor 4Q from the following expression... (answered by josmiceli)
(-8... (answered by AnlytcPhil)
Simplify:... (answered by Cromlix)
multiplication and division of rational expression;... (answered by algebrapro18)