SOLUTION: convert the equation to standard form by completing the square on x or y. then find the vertex, focus, and directrix of the parabola. finally, graph the parabola
x^2+14x-12y+13=
Algebra.Com
Question 1089165: convert the equation to standard form by completing the square on x or y. then find the vertex, focus, and directrix of the parabola. finally, graph the parabola
x^2+14x-12y+13=0
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
------This form of equation allows to easily find vertex, and distance from either focus or directrix.
Parabola has vertex as a minimum point.
Vertex (-7,-3)
-
-
Focus (-7,0)
Directrix y=-6,
RELATED QUESTIONS
Convert the equation to standard form by completing the square on x or y. Then find the... (answered by scott8148,terasse jade)
convert the equation to standard for by completing the square on x. Then find the vertex, (answered by MathLover1)
2. Given the equation f(x)=-3(x-4)(x+8), determine the following algebraically.... (answered by ewatrrr)
Find the vertex, focus, and directrix without completing the square, and deteremine opens (answered by lwsshak3)
Find the vertex, focus and directrix of the parabola y= -3x^2+12x-8 without completing... (answered by ewatrrr)
How do you convert the equation 4x^2+25y^2-24x+100y+36=0 to its standard form by... (answered by KMST)
1. Find the standard form of the equation of the parabola with a focus at (0, -9) and a... (answered by josgarithmetic)
How do I identify the equation (name the conic section), and then convert the equation to (answered by lwsshak3)
Convert the equation to the standard form for a hyperbola by completing the square on x... (answered by KMST)