SOLUTION: convert the equation to standard for by completing the square on x. Then find the vertex, focus and directrix of the parabola. then graph x^2+2x-8y-31=0

Question 1089163: convert the equation to standard for by completing the square on x. Then find the vertex, focus and directrix of the parabola. then graph
x^2+2x-8y-31=0

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

The "vertex" form of a parabola with its vertex at (,) is:
regular:
sideways:
The conics form of the parabola equation (the one you'll find in advanced or older texts) is:
regular:
sideways:
where the value of is actually the same as the value of

....since coefficients and , we have ->->

=> and , and
the vertex is at (,)
The focus is "p" units from the vertex:
,
so
then,
the focus is unit above the vertex, at (, ),
and the directrix is the horizontal line, p or below the vertex

RELATED QUESTIONS
convert the equation to standard form by completing the square on x or y. then find the... (answered by josgarithmetic)

Convert the equation to standard form by completing the square on x or y. Then find the... (answered by scott8148,terasse jade)

Please show the steps on how to solve: Find the vertex, focus, and directrix of the... (answered by ewatrrr)

I need details on how to solve this question: Find the vertex, focus and directrix of... (answered by ewatrrr)

How do I identify the equation (name the conic section), and then convert the equation to (answered by lwsshak3)

Convert the equation to the standard form for a hyperbola by completing the square on x... (answered by KMST)

Convert the equation to the standard form for a hyperbola by completing the square on x... (answered by lwsshak3)

Find the vertex, focus, and directrix of the parabola given by the equation... (answered by RAY100)

Find the vertex, focus, and directrix of the parabola given by the equation (x-1)^2 =... (answered by lwsshak3)