SOLUTION: Solve each equation on the interval [0,2pi) sin^2x-cos^2x=0

Question 1088052: Solve each equation on the interval [0,2pi)
sin^2x-cos^2x=0
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.

To solve it effectively, you must to know that

 = -cos(2x).


It is the direct consequence of the adding formula for cosine.


Then your equations becomes

cos(2x) = 0 

and has the solutions  x = , ,  and .

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