SOLUTION: CotA+tanB/tanA+cotB=cotA/tanB

SOLUTION: CotA+tanB/tanA+cotB=cotA/tanB

Algebra.Com

Question 1087221: CotA+tanB/tanA+cotB=cotA/tanB
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
CotA+tanB/tanA+cotB=cotA/tanB
-----------
I suspected that.
Thx for confirming it.

RELATED QUESTIONS
cotA+cotB/tanA+tanB=cotB/tanA (answered by Tatiana_Stebko)

TANA+COTB/COTA+TANB=TANA+COTB (answered by Edwin McCravy)

tanA+cotB/tanB+cotA=tanA*cotB (answered by Edwin McCravy)

CotA+cotB/tanA+cotB=cot/tanB (answered by Alan3354)

show that cotA + tanB / cotB + tanA... (answered by hamsanash1981@gmail.com)

Prove that (tanA - tanB)/(1 - tanAtanB) = (cotB - cotA)/cotBcotA - 1 (answered by MathLover1)

Which one of the following statements is true for trigonometric functions of two acute... (answered by vleith)

(tanA)(cotA) (answered by jim_thompson5910)

CotA =4/3 and (a+b)=90degree find the value of tanB = ? (answered by Aldorozos,ikleyn)