SOLUTION: please help me thank you. write the product as a sum using a product to sum identity. 2sin(x+6y)cos(x-6y).
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Question 1085917: please help me thank you. write the product as a sum using a product to sum identity. 2sin(x+6y)cos(x-6y).
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The trig identity we'll use is
\cos(\beta) = \frac{1}{2}\left(\sin(\alpha+\beta)+\sin(\alpha-\beta)\right))
which is from this list of trig identities (see the "Product to Sum Formulas" section on page 2)
In this case,
= alpha = x+6y
= beta = x-6y
So this means,
\cos(\beta) = \frac{1}{2}\left(\sin(\alpha+\beta)+\sin(\alpha-\beta)\right))
\cos(x-6y) = \frac{1}{2}\left(\sin(x+6y+x-6y)+\sin(x+6y-(x-6y))\right))
\cos(x-6y) = \frac{1}{2}\left(\sin(2x)+\sin(x+6y-x+6y)\right))
\cos(x-6y) = \frac{1}{2}\left(\sin(2x)+\sin(12y)\right))
\cos(x-6y) = \frac{1}{2}\sin(2x)+\frac{1}{2}\sin(12y))
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