SOLUTION: Tanxsin^2x=1.21tanx

Question 1084174: Tanxsin^2x=1.21tanx
Answer by ikleyn(53765) (Show Source): You can put this solution on YOUR website!
.

The only solution in the interval [,) are x= 0 ans x= .


The solutions on the number line are x = , k = 0, +/-1, +/-2, . . . 



The steps:


 =   ====>

 = 0  ====>

 = 0.


The term (sin^2(x) - 1.21) is NEVER zero.


Therefore, the only solutions come from tan(x) = 0.

Solved.

RELATED QUESTIONS
Tanxsin^2x-0.045=0 (answered by Alan3354)

Prove... (answered by Alan3354)

tanxsin^2... (answered by ikleyn)

when tanxsin^2x=tanx, and looking at the intervals [0,2pie) why is 0 and pie the only... (answered by jim_thompson5910)

2X+2X=12 2X-1... (answered by oscargut)

(2x-1)^2-2x (answered by Alan3354)

2x... (answered by Edwin McCravy)

2x/1-� (answered by Fombitz)

1/2x-1=-1 (answered by nyc_function)