SOLUTION: In triangle ABC, a=15cm, b=21cm, and m∠C=90 degree. Solve the triangle. Can someone help me with this? Thank you.

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Question 1077715: In triangle ABC, a=15cm, b=21cm, and m∠C=90 degree. Solve the triangle.
Can someone help me with this?
Thank you.

Found 4 solutions by Boreal, MathLover1, MathTherapy, Alan3354:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
This is a right triangle with legs 15 and 21. The hypotenuse or c, is sqrt (225+441)=sqrt(666)=25.81.
can use Law of Sines
25.81/sin C=25.81= a/sin A=15/sin A; sin A=15/25.81=0.5812. Take the arc sin (0.5812)=35.53 deg angle A
21/25.81=0.8136; arc sin (0.8136)=54.45 deg angle B

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

In triangle , , , and < degree.
use Law of Cosines:



......






















°

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
In triangle ABC, a=15cm, b=21cm, and m∠C=90 degree. Solve the triangle.
Can someone help me with this?
Thank you.
This is a right triangle, so for the missing side c, we get: 
To get the smaller angle (A), calculate:
To get ∡B, just subtract ∡A from 90o.
Why do the other people who responded make this problem look so complex?
Why would anyone want to use the law of cosines and/or the law of sines? Unless, of course, it is so requested?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
In triangle ABC, a=15cm, b=21cm, and m∠C=90 degree. Solve the triangle.
-----------
It's a right triangle, so c^2 = a^2 + b^2
======================
sin(A) = a/c
sin(B) = b/c

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