SOLUTION: Please help me to solve the problem 1) A town B is due north of A. A third town C is 10 km on a bearing 020�from A. If B is on a bearing of 290� from C, calculate

Question 1067936: Please help me to solve the problem 1) A town B is due north of A. A third town C is 10 km on a bearing 020�from A. If B is on a bearing of 290� from C, calculate (a) |BC| (b) |AB|

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
Bearings are measured clockwise from North, therefore
:
Angle BAC is 20 degrees
Angle ACB is 90 degrees
Angle ABC is 70 degrees
:
tan(20) = BC / 10
a) BC = 10 * tan(20) = 3.64 Km
:
sin(70) = 10 / AB
b) AB = 10 / sin(70) = 10.64 Km
:
Note that (3.64)^2 + 10^2 = (10.64)^2
:

RELATED QUESTIONS
Hi could you kindly solve this trig question with a diagram please. Town B is 40km... (answered by Alan3354)

town a b c form a right triangle on the map town c is 65.5 miles away from town b... (answered by josgarithmetic)

The following problem involves directions in the form of bearing, which we defined in... (answered by Alan3354)

A car travels from town P for 50km due North to town Q. It then travels 80km on bearing (answered by Alan3354)

A plane is flying on a bearing of 237 degrees from Town A to Town C which is 364 km away. (answered by Theo,richwmiller)

Town C is 9 miles due east of town D. Town E is 17 miles from town C at a bearing (from... (answered by TimothyLamb)

Please help me solve this equation: Distance between the cities A - B is 125 km. Dan... (answered by jorel555,ikleyn)

driving from town A to town D, you pass thru town B then town C. town A to town B is 10... (answered by Fombitz,stanbon)

A person can drive from town A to town B at a certain rate of speed in 6 hours. If he... (answered by mananth)