SOLUTION: Let θ be an angle in quadrant II such that sinθ=3/5. Find the exact values of secθ and cotθ.

Algebra.Com
Question 1063557: Let θ be an angle in quadrant II such that sinθ=3/5.
Find the exact values of secθ and cotθ.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Step 1, find the cosine.
cosine is negative in Q2
---
sec = 1/cos
cot = cos/sin

RELATED QUESTIONS

Let θ be an angle in quadrant II such that secθ=-(13)/(12) Find the exact... (answered by stanbon,solver91311)
Let θ be an angle in quadrant II such that =sinθ(4/5) Find the... (answered by lwsshak3)
Let θ be an angle in quadrant IV such that sinθ =−5/8 . Find the exact (answered by Edwin McCravy)
Let θ be an angle in quadrant II such that sinθ= 12/13 Find the exact... (answered by stanbon)
Let θ be an angle in quadrant II such that =cosθ−35 . Find... (answered by ikleyn)
Let θ be an angle in quadrant IV such that sinθ=-5/13 Find the exact values of (answered by Fombitz)
Let θ be an angle in quadrant IV such that cosθ= 4/9 Find the exact values... (answered by lwsshak3)
Find the values of the trigonometric functions of θ if csc θ = 13/9 and... (answered by Alan3354,ewatrrr)
If secθ= 4/3 and θ terminates in Quadrant IV, find the exact values for all six (answered by lwsshak3)