SOLUTION: Let θ be an angle in quadrant II such that sinθ=3/5.
Find the exact values of secθ and cotθ.
Algebra.Com
Question 1063557: Let θ be an angle in quadrant II such that sinθ=3/5.
Find the exact values of secθ and cotθ.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Step 1, find the cosine.
cosine is negative in Q2
---
sec = 1/cos
cot = cos/sin
RELATED QUESTIONS
Let θ be an angle in quadrant II such that secθ=-(13)/(12)
Find the exact... (answered by stanbon,solver91311)
Let
θ
be an angle in quadrant
II
such that
=sinθ(4/5)
Find the... (answered by lwsshak3)
Let θ be an angle in quadrant IV such that sinθ =−5/8
.
Find the exact (answered by Edwin McCravy)
Let θ be an angle in quadrant II such that sinθ= 12/13
Find the exact... (answered by stanbon)
Let
θ
be an angle in quadrant
II
such that
=cosθ−35
.
Find... (answered by ikleyn)
Let θ be an angle in quadrant IV such that sinθ=-5/13
Find the exact values of (answered by Fombitz)
Let θ be an angle in quadrant IV such that cosθ= 4/9
Find the exact values... (answered by lwsshak3)
Find the values of the trigonometric functions of θ if csc θ = 13/9
and... (answered by Alan3354,ewatrrr)
If secθ= 4/3 and θ terminates in Quadrant IV, find the exact values for all six (answered by lwsshak3)