SOLUTION: How do you prove (sin[theta]tan[theta])/1-(cos[theta])= 1+(sec[theta])

Question 1062557: How do you prove (sin[theta]tan[theta])/1-(cos[theta])= 1+(sec[theta])
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do you prove (sin[theta]tan[theta])/1-(cos[theta])= 1+(sec[theta])
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sin*tan/(1 - cos) = 1 + sec
sin^2/cos/(1-cos) = 1 + sec
Multiply cos
sin^2/(1-cos) = cos + 1
Multiply by 1-cos
sin^2 = 1 - cos^2
I'm convinced.

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