SOLUTION: Find each exact value if 0 < x < pi/2 and 0 < y < pi/2 Cos(x-y) if sinx= 7/25 and cosy= 2/3 This is what I have so far: cosa•cosB+sina•sinB (7/25)(2/3)+(7/25)(sqrt5/3) 14/75

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Question 1061974: Find each exact value if 0 < x < pi/2 and 0 < y < pi/2
Cos(x-y) if sinx= 7/25 and cosy= 2/3
This is what I have so far:
cosa•cosB+sina•sinB
(7/25)(2/3)+(7/25)(sqrt5/3)
14/75+7sqrt5/75
14+7sqrt5/75
I'm not sure if I'm finished with the problem or if I have more steps or if I have just done the problem completely wrong. The answer doesn't match the key so I'm curious as to what I'm doing wrong. Thank you!

Found 2 solutions by MathTherapy, ikleyn:
Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!
Find each exact value if 0 < x < pi/2 and 0 < y < pi/2
Cos(x-y) if sinx= 7/25 and cosy= 2/3
This is what I have so far:
cosa•cosB+sina•sinB
(7/25)(2/3)+(7/25)(sqrt5/3)
14/75+7sqrt5/75
14+7sqrt5/75
I'm not sure if I'm finished with the problem or if I have more steps or if I have just done the problem completely wrong. The answer doesn't match the key so I'm curious as to what I'm doing wrong. Thank you!
Find each exact value if 


cos (A - B) = cos A cos B + sin A sin B ---- Difference of 2 angles' formula
cos (x - y) = cos x cos y + sin x sin y ---- Replacing A with x, and B with y 


It's obvious that we need cos x and sin y

We see that a 7-24-25 Pythag triple ensues, and therefore, x = 24
We now have: 




_____
We now have: 

cos (x - y) = cos x cos y + sin x sin y now becomes: 
cos (x - y) =  ------- Substituting 
Up to this point, you seem to have gotten , but .
You should be able to complete it, now that you know where your mistake was.


Note that since it was stated that: , the angles are in the 1st quadrant.

Answer by ikleyn(52880)   (Show Source): You can put this solution on YOUR website!
.
For other examples of similar solved problems see the lessons
    - Calculating trigonometric functions of angles
    - Advanced problems on calculating trigonometric functions of angles
in this site.

Also, you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Trigonometry: Solved problems".


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