SOLUTION: find the intervals on which f(x)= 2x^3 - 3x^2 is increasing. find the intervals on which f(x)= 2x^3

SOLUTION: find the intervals on which f(x)= 2x^3 - 3x^2 is increasing. find the intervals on which f(x)= 2x^3 - 3x^2 is concave down.

Question 1059519: find the intervals on which f(x)= 2x^3 - 3x^2 is increasing.
find the intervals on which f(x)= 2x^3 - 3x^2 is concave down.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
first derivative

Know the basic shape of cubic polynomial or function!
Maximum at x=0 and minimum and x=1.
You can figure the intervals of the function increasing.

Second derivative

-----------this is where you find the inflection point, and again, understanding the shape of cubic functions, the interval on which f is concave downward is (-infinity, 1/2 ).
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