SOLUTION: 2cos(2x)^2 - cosx + 2sin2x = 1 where x is between [-π/2 , 3π/2]

SOLUTION: 2cos(2x)^2 - cosx + 2sin2x = 1 where x is between [-π/2 , 3π/2]

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Question 1058528: 2cos(2x)^2 - cosx + 2sin2x = 1 where x is between [-π/2 , 3π/2]
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
2cos(2x)^2
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Is that 2cos(4x^2) ?
Or 2cos^2(2x) ?
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