SOLUTION: How do you solve the equation with the following domain? -2π ≤ x ≤ 2π
4sin^2x -3=0
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Question 1054105: How do you solve the equation with the following domain? -2π ≤ x ≤ 2π
4sin^2x -3=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you solve the equation with the following domain? -2π ≤ x ≤ 2π
4sin^2x -3=0
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sin^2(x) = 3/4
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sin(x) = +-sqrt(3)/2
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x = +-pi/3 ; x = +-(2/3)pi
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Cheers,
Stan H.
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