SOLUTION: Please help me solve this problem!
If cosx = 1/5. Find all possible values of secx - tanx/ sinx.
Now, the answer at the back of the book is: {{{(25sqrt(6) - 60)/12}}} ; {{{(-
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Question 1052209: Please help me solve this problem!
If cosx = 1/5. Find all possible values of secx - tanx/ sinx.
Now, the answer at the back of the book is: ;
I just can't quite get there. I know you have to turn everything into cos, because that is what you have a value for.
So I got: 1/cosx - sinx/cosx for the numerator. You can add these because the denominators are the same. So it would be: 1 - sinx/cosx. And all of this over sinx.
Then I thought, hmmmm, what if I were to multiply the numerator and denominator by sinx. That would give me: sinx - sin^2x / cosx / sin^2x. And sin^2x = 1 - cos^2x, so that takes care of that, but I still have that sinx at the beginning that I can't get rid of. :(
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
Please help me solve this problem!
If = , Find all possible values of
This is long but bear with me.
if = then
+=
+=
+=
=-
=-
thus
= or =-
remember that
=
*
*
*
**
simplify to get
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